Raphael Viñoly Tower to be South Loop’s Tallest Skyscraper; Could be a Twin

Architect Rafael Viñoly next to a model of 113 East Roosevelt

Architect Rafael Viñoly next to a model of 113 East Roosevelt

The long-vacant corner southeast corner of South Michigan Avenue and East Roosevelt Road is getting a building worthy of its prominent position in the South Loop.

Model of 113 East Roosevelt

Model of 113 East Roosevelt

Plans have been unveiled for an 829-foot-tall skyscraper at the location which would be the tallest in the South Loop, and 13th tallest in the city of Chicago, behind the Park Tower up the street at 800 North Michigan Avenue.

The Chicago Architecture Blog’s Zachary Pollack was at the event hosted by 3rd Ward Alderman Pat Dowell  and had these thoughts:

There is no denying [this would] be a structure not only significant for the Third Ward, but for Chicago as a city.  Starchitect Rafael Viñoly graced Chicago with his presence to showcase his proposed design for Crescent Height’s newest South Loop development: a 76 story rental tower at 113 East Roosevelt Road.

As Viñoly stated, the tower will act as a “structural bookmark” for the south side of Grant Park. Even more exciting is that if the market permits Crescent Heights to get its way there is a plan for a second, almost identical tower to sit adjacent to the first. Crescent Height’s attorney stated that the developer anticipates this second tower will consist of condominium units.

Quick facts:

  • Address: 113 East Roosevelt Road
  • Developer: Crescent Heights
  • Architect: Rafael Viñoly
  • Height: 829 feet
  • Stories: 76
  • Retail space: 12,005 square feet
Location: 113 East Roosevelt Road, South Loop

Editor

Author: Editor

Editor founded the Chicago Architecture Blog in 2003, after a long career in journalism. He can be reached at chicagoarchitectureinfo@gmail.com.

Share This Post On

Submit a Comment

Your email address will not be published. Required fields are marked *

Human Verification: In order to verify that you are a human and not a spam bot, please enter the answer into the following box below based on the instructions contained in the graphic.